51. Incorrect. The answer is true not false. Recall that in the
input output matrix, the inputs into X1 go down,
inputs in X2 go down, etc. So the input output matrix is
A |
X1 |
X2 |
X3 |
X4 |
X1 |
0.10 |
0.12 |
0.15 |
0.16 |
X2 |
0.11 |
0.30 |
0.17 |
0.18 |
X3 |
0.20 |
0.25 |
0.13 |
0.14 |
X4 |
0.40 |
0.21 |
0.40 |
0.22 |
For the equations, we need X1
inputs into each of the outputs, which go across. So the equations are:
X1 = 0.10X1 + 0.12X2 + 0.15X3 + 0.16X4 + 12
X2 = 0.11X1 + 0.30X2 + 0.17X3 + 0.18X4 + 15
X3 = 0.20X1 + 0.25X2 + 0.13X3 + 0.14X4 + 150
X4 = 0.40X1 + 0.21X2 + 0.40X3 + 0.22X4 + 10
The first four expressions to
the right of the equal sign are the amount of X1 used as intermediate product
and the last expression 12 is the end- use demand. The solution to this problem is:
X1=144.223
X2=196.141
X3=309.973
X4=298.549