16. Incorrect. The answer is false not true. Let's define the following events: A: low-quality gold ore, and B: non-precious ore. We can write the probability as follows: P(A∩B). The problem is that in this case both events are not independent According to Schaums' Outline the probability of such an event is: P(A∩B) = P(B/A)*P(A) where P(B/A) is the conditional probability (the probability of B given that A has occurred). So, we have that: P(A) = 1/18 and P(B|A) = 12/17. Therefore P(A∩B) = (1/18)*(12/17) = 12/306 ≈0.04 or 4%.