**1. Correct. The
answer is true**

The probability of drilling a successful well is p=0.1. The probability of drilling an unsuccessful well is q = (1-p) = 0.9. Let the random variable X be the number of successful wells. You can model this phenomenon by using a binomial distribution. This distribution is defined as follows:

_{}

*n**!* is a *factorial
number*: n*(n-1)*(n-2). . .3*2*1, and *n*
is the number of trials. Therefore:

(a) _{}

P(X = 1) = 0.2916 or 29.16%

(b) P(X < 2) = P(X=0) + P(X=1) = _{}

P(X < 2) = 0.6561 + 0.2916

P(X < 2) = 0.9477 or 94.77%