7. Incorrect. The answer is true not false.
The mean of the sampling distribution of means would be identical to the population mean, i.e. 1% for both cases. The standard deviation for the case with replacement would be:
σ /√n = 0.02/√50 = 0.0028
and without replacement
(σ /√n)*( √((N-n)/9N-1)) = (0.02/√50)(( √100-50)/(100-1)) = 0.002