8. Correct. The answer is false

 

The confidence limits should be calculated using the standard deviation of the sampling distribution of means and not the population standard deviation. Thus for 95% we have Zc= 1.96 and for 99% we have Zc= 2.58. Thus for 95% the limits are:

 

`x + Zc(s/√n) = 2000 + 1.96(200/√1000) = 2000 + 12.4 m

 

For 99%

`x + Zc(s/√n) = 2000 + 2.58(200/√1000) = 2000 + 6.3 m