**8. Incorrect. The answer is
false, not true**

The confidence limits should be calculated using the standard deviation
of the sampling distribution of means and not the population standard
deviation. Thus for 95% we have Zc= 1.96 and for 99%
we have Zc= 2.58. Thus for 95% the limits are:

`x __+__ Zc(s/√n)
= 2000 __+__ 1.96(200/√1000) = 2000 __+__ 12.4 m

For 99%

`x __+__ Zc(s/√n) = 2000 __+__ 2.58(200/√1000)
= 2000 __+__ 6.3 m