8. Incorrect. The answer is
false, not true
The confidence limits should be calculated using the standard deviation
of the sampling distribution of means and not the population standard
deviation. Thus for 95% we have Zc= 1.96 and for 99%
we have Zc= 2.58. Thus for 95% the limits are:
`x + Zc(s/√n)
= 2000 + 1.96(200/√1000) = 2000 + 12.4 m
For 99%
`x + Zc(s/√n) = 2000 + 2.58(200/√1000)
= 2000 + 6.3 m