8. Incorrect. The answer is false, not true

 

The confidence limits should be calculated using the standard deviation of the sampling distribution of means and not the population standard deviation. Thus for 95% we have Zc= 1.96 and for 99% we have Zc= 2.58. Thus for 95% the limits are:

 

`x + Zc(s/√n) = 2000 + 1.96(200/√1000) = 2000 + 12.4 m

 

For 99%

`x + Zc(s/√n) = 2000 + 2.58(200/√1000) = 2000 + 6.3 m