11. Incorrect. The answer is false, not true


Given the confidence interval for 95 % which is

, also given the following parameters , ,


Using the 95% Level of confidence z = 1.96

95% confidence interval for m is


and therefore




For 95% of the samples the true population mean () lies in the interval .

Or the average number of days off sick for employees in the population is likely to be between 7.71 and 8.69.