**8. Correct. The
answer is true.**

m=15, n=10, s_{1}^{2}=24 and s_{2}^{2}=16,
so that

(estimated s_{1}^{2})=s_{1}^{2}*m/(m-1) = 24*15/14=25.71

(estimated s_{2}^{2})=s_{2}^{2}*n/(n-1) = 16*10/9=17.78

From the F-table, for n_{1}=14 and n_{2}=9
F_{0.95}=3.01 and F_{0.05}=1/2.59. Thus the 90% confidence
interval is

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