8. Correct. The answer is false

The test can be formulated as follows

H₀: μ=0.100

H_a: μ> 0.100

Under the H₀, t₀=(X_bar-μ₀)(n)^0.5/s=(0.106-0.100)*16^0.5/0.012=2.0

At 0.05 level of significance the decision rule is to reject H₀ if t_0.05,15 = 1.753 < t₀, where a=0.05 and there are 16-1=15 degrees of freedom. Since t₀=2, we reject H₀ at the 5% level.

At 0.01 level of significance the decision rule is to reject H₀ if t_0.01,15 = 2.602 < t₀, where a=0.05 and there are 16-1=15 degrees of freedom. Since t₀=2, we fail to reject H₀ at the 1% level.