1. Correct. The answer is false.

a) The equation of the line is y=a+bx. The normal equations are

Σy=an+bΣx

Σxy=aΣx+bΣx².

X	y	x^2	xy	y^2(for part (b))
1	1	1	1	1
3	2	9	6	4
4	4	16	16	16
6	4	36	24	16
8	5	64	40	25
9	7	81	63	49
11	8	121	88	64
14	9	196	126	81
Σx=56	Σy=40	Σx^2=524	Σxy=364	Σy^2=256

Since n=8, the normal equations become

8a=56b=40

56a+524b=364

Solving simultaneously, we obtain a=0.545 and b=0.636 and y=0.545 + 0.636x.

b) The equation of the line is x=c+dy and the normal equations are

Σx=cn+dΣy

Σxy=cΣy+dΣy².

Using the data from the above table, the normal equations become

8c+40d=56

40c+256d=364.

Solving simultaneously, we obtain c=-0.5 and d=1.5 and x=-0.5 + 1.5y.