**2. Correct. The
answer is true**

Case a. x is the independent variable.

y=a+bx (1)

Sy=an+bΣx (2), dividing this by n gives

`y=a+b`x (3).

Subtracting (3) from (1):

y-`y=b(x-`x), which shows that the line passes through (`x,`y).

Case b. y is the independent variable.

x=c+dy (1)

Sx=cn+dΣy (2), dividing this by n gives

`x=c+d`y (3).

Subtracting (3) from (1):

x-`x=d(y-`y), which shows that the line passes through (`x,`y).