2. Incorrect. The
answer is true not false.
Case a. x is the independent variable.
y=a+bx (1)
Sy=an+bΣx (2), dividing this by n gives
`y=a+b`x (3).
Subtracting (3) from (1):
y-`y=b(x-`x), which shows that the line passes through (`x,`y).
Case b. y is the independent variable.
x=c+dy (1)
Sx=cn+dΣy (2), dividing this by n gives
`x=c+d`y (3).
Subtracting (3) from (1):
x-`x=d(y-`y), which shows that the line passes through (`x,`y).