**7. Correct. The
answer is false.**

T=( b - b)*(n-2)^{2}/(s_{y.x}/s_{x})=(0.636-0.454)*6^{0.5}/(0.5641/4.062)=3.2095

Since s_{y.x}=0.5641 was
computed in problem 8.4 and s_{x}=(`x^{2}-(`x)^{2})^{0.5}=4.062 follows from problem 1.

On the basis of one-tailed t-test, we would reject the
hypothesis that the regression coefficient is as low as 0.454 if t>t_{0.95}=1.94
for 8-2=6 degrees of freedom. Thus we reject the hypothesis.